(1, π/4)的直角坐标为(√2/2, √2/2)此圆的直角坐标方程为(x-√2/2)²+(y²-√2/2)²=1展开得: x²+y²-√2(x+y)=0代入x=pcosθ, y=psinθ, 得极坐标方程：p²-√2p(cosθ+sinθ)=0得：p=√2(cosθ+sinθ)
