∵|x+1|=3 且 |y-1|=2
∴可以得出x和y的四组解,分别为
(1)x=2, y=3
(2)x=2, y=-1
(3)x=-4, y=3
(4)x=-4, y=-1
A=(3x+2y)^2, B=x^2-2xy-y^2,
A+B = 9x^2+12xy+4y^2+x^2-2xy-y^2
= 10x^2+10xy+3y^2
把以上四组解分别代入,
得:
(1)A+B=127
(2)A+B=23
(3)A+B=67
(4)A+B=203
|x+1|=3 且 |y-1|=2
可得(1)x=2, y=3
(2)x=2, y=-1
(3)x=-4, y=3
(4)x=-4, y=-1
A=(3x+2y)^2, B=x^2-2xy-y^2,
A+B = 9x^2+12xy+4y^2+x^2-2xy-y^2
= 10x^2+10xy+3y^2
则
(1)A+B=127
(2)A+B=23
(3)A+B=67
(4)A+B=203