对已知条件(A+B)/(A-B)=(2x+y)/(x-y),两边取倒数得,
(A-B)/(A+B)=(x-y)/(2x+y);
因此,1-2B/(A+B)=(x-y)/(2x+y);
B/(A+B)=[1-(x-y)/(2x+y)]/2
=[(x+2y)/(2x+y)]/2;
故A/(A+B)
=(x-y)/(2x+y)+B/(A+B)
=(x-y)/(2x+y)+[(x+2y)/(2x+y)]/2
=[(2x-2y+x+2y)/(2x+y)]/2
=3x/[2(2x+y)]
=3x/(4x+2y);