(x+1)/(x+1)(x-1) -1/3x=1/3(x-1)
1/(x-1)-1/3x=1/3(x-1)
两边乘以3x(x-1)得
3x-(x-1)=x
3x-x+1=x
x=-1
检验：x=-1是增根
(x+2)/(x-2) +(x+2)(x-2)/(3x+1)(x-2)=1
两边乘以(3x+1)(x-2)得
(x+2)(3x+1)+(x+2)(x-2)=(3x+1)(x-2)
(x+2)(3x+1)-(3x+1)(x-2)+x²-4=0
12x+4+x²-4=0
x²+12x=0
∴x=0 x=-12
检验：x=0，x=-12是方程的解
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